8r^2-23r-36=)

Solution for 8r^2-23r-36=) equation:

8r^2-23r-36=)

We move all terms to the left:

8r^2-23r-36-())=0

We add all the numbers together, and all the variables

8r^2-23r=0

a = 8; b = -23; c = 0;
Δ = b2-4ac
Δ = -232-4·8·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-23}{2*8}=\frac{0}{16}
=0
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+23}{2*8}=\frac{46}{16}
=2+7/8
$